The density of 3 m solution of NaOH is 1.110 | vedclass

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(A) $3 \ m$ solution of $NaOH$ means $3 \ moles$ of $NaOH$ are dissolved in $1000 \ g$ of solvent.Molar mass of $NaOH = 23 + 16 + 1 = 40 \ g \ mol^{-1

Vedclass · Accepted Answer

$2.97$

Vedclass · Answer

(A) $3 \ m$ solution of $NaOH$ means $3 \ moles$ of $NaOH$ are dissolved in $1000 \ g$ of solvent.Molar mass of $NaOH = 23 + 16 + 1 = 40 \ g \ mol^{-1}$.Mass of $NaOH = 3 \ moles 	imes 40 \ g \ mol^{-1} = 120 \ g$.Total mass of solution = Mass of solvent + Mass of solute = $1000 \ g + 120 \ g = 1120 \ g$.Volume of solution = $\frac{	ext{Mass}}{	ext{Density}} = \frac{1120 \ g}{1.110 \ g \ mL^{-1}} \approx 1009.01 \ mL$.Molarity $(M)$ = $\frac{	ext{Moles of solute} 	imes 1000}{	ext{Volume of solution in } mL} = \frac{3 	imes 1000}{1009.01} \approx 2.97 \ M$.

The density of $3 \ m$ solution of $NaOH$ is $1.110 \ g \ mL^{-1}$. Calculate the molarity of the solution. (in $M$)

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